If an object is thrown downward with an initial velocity of v 0 , then the distance it travels is given by sequals4.9tsquaredplusv 0t. An object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. What was the initial velocity of the object?

Initial velocity of the object = 31.4 m/s

Explanation:

If an object is thrown downward with an initial velocity of v₀ , then the distance it travels is given by s = 4.9 t²+v₀t

Now an object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. We need to find initial velocity of the object.

s = 4.9 t²+v₀t

138.3 = 4.9 x 3² + v₀ x 3

3v₀ = 94.2

v₀ = 31.4 m/s

Initial velocity of the object = 31.4 m/s