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29 December, 18:22

An l-c circuit has an inductance of 0.450 h and a capacitance of 0.200 nf. during the current oscillations, the maximum current in the inductor is 1.40

a. part a what is the maximum energy e max stored in the capacitor at any time during the current oscillations?

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Answers (2)
  1. 29 December, 18:34
    0
    Energy = 0.441 J

    Explanation:

    Given:

    Inductance, L = 0.45 H

    Capacitance, C = 0.200 nF

    = 0.2 * 10^9 F

    Current, I = 1.4 A

    Energy, E = 1/2 * L * I^2

    = 1/2 * 0.45 * (1.4) ^2

    = 0.441 J
  2. 29 December, 22:22
    0
    0.441 J

    Explanation:

    The maximum energy stored in the capacitor = maximum energy stored in inductor, E = 1/2Li². where L = inductance = 0.450 H and i = current = 1.40 A

    E = 1/2Li² = 1/2 * 0.45 * 1.40² = 0.441 J
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