During a tennis match, a player serves the ball at a speed s, with the center of the ball leaving the racquet at angle θ below the horizontal at a height y0. The net is a distance d away and has a height h. When the ball is directly over the net, what is the distance between them?

Question

Physics

Tucker Sampson

11 September, 03:03

During a tennis match, a player serves the ball at a speed s, with the center of the ball leaving the racquet at angle θ below the horizontal at a height y0. The net is a distance d away and has a height h. When the ball is directly over the net, what is the distance between them?

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Answers (1)

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Armani · Answer 1

Answer: Maximum distance

= {s²/g} * sine (2*theta) unit

Explanation: This is a projectile motion problem. The horizontal distance between the tennis player and where the tennis reaches over the net is given by the horizontal Range.

Range = {s² * sine2*theta}/g

(s) is the initial speed of projection

Theta is the angle of projection

g is acceleration due to gravity 10m/s².