Ask Question
15 November, 00:25

A car traveling 67 mph (30 m/s) accelerates for 3 seconds in order to reach a speed of 100 mph (45 m/s). a. What is the acceleration of the car in m/s^2

b. How far does it travel in m?

+5
Answers (1)
  1. 15 November, 02:57
    0
    a. a = 5 m/s^2

    b. distance traveled = 112.5 m

    Explanation:

    Acceleration is the rate of variation of the velocity of an object when it moves. If the object in question maintains its speed constantly, then it is not accelerating, something it will do when its speed changes. Acceleration is measured in meters per second squared, and it is based on the time it takes to move from one speed to another, or a force that is applied to the object.

    In order to calculate it, it is essential that you know the acceleration formula (a = Δv / Δt). In it, "a" is the acceleration, "Δv" is the variation of the velocity and "Δt" is the time in that variation.

    Calculation

    a = Δv / Δt

    a = (45 m/s - 30 m/s) / (3 s - 0 s)

    a = 5 m/s^2

    To calculate the distance we need the average speed that he obtained in those 3 seconds

    average speed: (45 m/s + 30 m/s) / 2 = 37.5 m/s

    distance traveled = average speed * time

    distance traveled = 37.5 m/s * 3 s

    distance traveled = 112.5 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A car traveling 67 mph (30 m/s) accelerates for 3 seconds in order to reach a speed of 100 mph (45 m/s). a. What is the acceleration of the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers