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16 November, 17:21

The propeller of a World War II fighter plane is 2.30 m in diameter and spins at 1200 rev/min.

What is the centripetal acceleration of the propeller tip?

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  1. 16 November, 18:14
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    Answer: centripetal acceleration

    Equals 18350m/s²

    Explanation: Centripetal acceleration is given as v²/r

    Where v is Velocity measured in rad/s and r is radius

    But v = w*r

    Therefore,

    C. acceleratn = w²*r²/r

    So we have

    C. accelertn = w²*r

    Our w is given as 1200 rev/min so we have to convert to rad/sec

    1rad/sec equals 9.5rev/min

    Therefore,

    1200rev/min = 1200/9.5 rad/sec

    w=126.32rad/sec

    r = diameter/2

    r = 2.3/2 = 1.15m

    Let's now calculate our centripetal acceleration = w²*r

    = {126.32rad/sec}² * 1.15

    =18350m/s²
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