Ask Question
8 November, 16:14

You set out to reproduce Thomson's e/m experiment with an accelerating potential of 150 V and adeflecting electric field of magnitude 6.0 * 106 N/C (a) At what fraction of the speed of light do the electrons move? (b) What magnetic-field magnitude will yield zero beam deflection? (c) With this magnetic field, how will the electron beam behave if you increase the acceleratingpotential above 150 V?

+5
Answers (1)
  1. 8 November, 19:26
    0
    a. v' = 24.22 x 10 ⁻³

    b. β = 0.825 T

    Explanation:

    V = 150 V, E = 6.0 x 10 ⁶ N / C

    a.

    ¹/₂ * m * v² = e * V

    v = √ 2 * e / m * V

    v = √ 2 * 1.76 x 10 ¹¹ * 150 v = √ 5.28 x 10 ¹³

    v = 7.26 x 10 ⁶ m / s

    v' / c = 7.26 x 10 ⁶ m / s / 3.0 x 10 ⁸ = 24.22 x 10 ⁻³

    b.

    β = E / V

    β = 6.0 x 10 ⁶ / 7.266 x 10 ⁶

    β = 0.825 T

    c.

    When the increasing the accelerating potential speed it doesn't change the up wired the electric force and the magnetic force the electron be beat down more.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “You set out to reproduce Thomson's e/m experiment with an accelerating potential of 150 V and adeflecting electric field of magnitude 6.0 * ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers