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28 February, 01:20

A proton starting from rest travels through a potential of 1.0 kV and then moves into a uniform 0.040-T magnetic field. What is the radius of the proton's resulting orbit? (mproton=1.67 * 10-27 kg, e = 1.60 * 10-19 C)

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  1. 28 February, 04:38
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    In the region of potential difference, protons will acquire velocity which can be found as follows

    1/2 m v² = Ve, V is potential diff, v is velocity attained, m is mass of proton, e is charge on proton

    v² = 2Ve / m

    For circular path of proton in a magnetic field

    mv² / r = Bev r is radius of circular path.

    r = mv / Be

    r² = m²v² / B²e²

    = 2Ve/m x m² / B²e²

    = 2Vm / B²e

    = 2 x 1000 x 1.67 x 10⁻²⁷ / (.04² x 1.6 x 10⁻¹⁹)

    =.013

    r =.114 m

    = 11.4 cm
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