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21 July, 03:24

A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s. Calculate the centripetal acceleration of the child. Calculate the net horizontal force exerted on the child. (mass = 28.5 kg).

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  1. 21 July, 06:36
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    Acceleration = 2.21m/s^2

    Force = 62.99N

    Explanation:

    Centripetal acceleration = v^2 / r

    Given velocity v = 2.05m/s

    Radius r = 1.90m

    Centripetal acceleration = (2.05) ^2 / 1.90

    2.05 x 2.05 / 1.90

    4.2025/1.90

    2.21m/s^2

    Now, since a = 2.21 m/s^2

    And mass m = 28.5kg

    Force exerted on the child = mass x centripetal acceleration

    That's 28.5kg x 2.21m/s^2

    62.99N
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