A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

Question

Physics

Tianna

19 October, 13:08

A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

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Answers (1)

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Brennan Smith · Answer 1

Given:

Mass, M = 80 kg

Acceleration due to gravity, g = 9.81 m/s^2

Radius, R = 3 m

Normal force, N = M * a

= M * v/t

Centripetal force, Fc = M * v^2/R

Fc = N

a = v^2/R

v = sqrt (9.81 * 3)

= 5.425 m/s

v = w * R

w = angular velocity

w = 5.425/3

= 1.808 rad/s