A Frisbee of radius 0.15 m is accelerating at a constant rate from 7.1 revolutions per second to 9.3 revolutions per second in 6.0 s. What is its angular acceleration?

Answer: 17.03 rad/s^2

Explanation: One of the equation of motion that defines a circular motion with constant acceleration is given below as

ω = ω0 + αt

Where ω = final angular velocity = 9.3 rev/s

ω0 = initial angular velocity = 7.1 rev/s

α = angular acceleration = ?

t = time taken = 6.0s

By substituting the parameters, we have that

9.3 = 7.1 + α (6)

9.3 - 7.1 = 6α

16.3 = 6α

α = 16.3/6

α = 2.71 rev/s^2

We can also give the answer in rad/s^2 (another unit of angular acceleration) by multipying by 2π

Hence, α = 2.71 * 2π, where π = 3.142

α = 17.03 rad/s^2