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11 May, 01:03

A baseball is popped straight up into the site and has a hang time of 6.25s determine the height to which the ball rises before it reaches its peak.

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Answers (2)
  1. 11 May, 03:52
    0
    47.9 m

    Explanation:

    Given:

    t = 6.25/2 = 3.125 s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: Δy

    Δy = vt - ½ at²

    Δy = (0 m/s) (3.125 s) - ½ (-9.8 m/s²) (3.125 s) ²

    Δy = 47.9 m
  2. 11 May, 04:42
    0
    Answer:A baseball is popped straight up into the air and has a hang-time of 6.25s. Hint: the time to rise to the peak is one-half the total hang-time.
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