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25 July, 03:37

In a quasi-static isobaric expansion, the gas does 26.4 J of work. The initial pressure and volume of the gas is 0.9 atm and 19 L. If the internal energy of the gas increases by 80 J in the expansion, how much heat does the gas absorb?

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  1. 25 July, 06:16
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    Q = 106.4 J

    Explanation:

    Given that

    Process is isobaric.

    Work done by gas (W) = 26. 4 J

    Volume of the gas at initial condition = 0.9 L

    Volume of the gas at final condition = 19 L

    Increase in the internal energy of gas = 80 J

    we know that from first law of thermodynamics

    Q = ΔU + W

    Here Q is the heat absorb by gas

    ΔU change in internal energy of gas

    W is the work done by gas

    So now by putting the values

    Q = ΔU + W

    Q = 80 + 26.4

    Q = 106.4 J
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