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4 October, 20:03

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process? Explain your answer.

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  1. 4 October, 23:38
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    4.80 kW

    Explanation:

    Power = work / time

    P = 100,832 J / 21.0 s

    P ≈ 4800 W
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