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13 May, 23:19

The acceleration function (in m/s2) and the initial velocity are given for a particle moving along a line. a (t) = t + 6, v (0) = 3, 0 ≤ t ≤ 11 (a) Find the velocity at time t. v (t) = Correct: Your answer is correct. m/s (b) Find the distance traveled during the given time interval.

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  1. 14 May, 02:46
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    a) V = 187 s

    b) d = 2024 m

    Explanation:

    Data

    a (t) = t + 6

    vo = 3

    0≤t≤11

    a) Find the velocity at that time

    When the time = 11

    a (11) = 11 + 6 = 17 m/s²

    and a = v/t, so v = at

    finally v = (17 m/s²) (11s)

    v = 187 m/s

    b) Find the distance traveled during the given time interval

    Vtotal = Vfinal - v initial

    v final = 187 m/s vinitial = 3 m/s

    V total = 187 - 3 = 184 m/s

    and Velocity = distance/time

    then distance = velocity x time

    so distance = 184 m/s x 11 s

    distance = 2024 m
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