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31 May, 18:05

By simultaneously conserving energy and momentum, calculate the energy of the neutron emitted in the forward direction by a beam of 150 keV deuterons undergoing the D-T reaction in a tritium target.

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  1. 31 May, 21:50
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    Answer: 2372Kev

    Eg = 2222keV

    Eex = ?

    Eex - Eg = 150keV

    Eex - 2222 = 150

    Eex = 150 + 2222

    Eex = 2372keV

    Explanation:

    The energy possessed by the deuterium particles in their ground state or unexcited state is Eg and in that in their excited state is Eex
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