A battery operating a large flashlight produces a current of 2 amperes in a lightbulb that has a resistance of 2.4 ohms. The voltage of the battery is:

Voltage of the battery = 4.8 volt

Explanation:

It is given that the flashlight produces a current of 2 ampere

So current i = 2A

And the resistance R = 2.4 ohm

We have to find the voltage of the battery

According to ohm's law voltage of the battery is given by = current * resistance

So voltage = 2*2.4 = 4.8 volt

The voltage of the battery depends on the current and resistance.