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22 April, 06:10

2 In a hydraulic press a force of 20 N is applied to a piston of

area 0.20 m2. The area of the other piston is 2.0 m2. What is

a the pressure transmitted through the liquid,

b the force on the other piston?

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Answers (1)
  1. 22 April, 07:24
    0
    Let index 1 refer to the pisyon with smaller section. And index 2, to the other piston.

    F1=20N

    S1=0.2m²

    S2=2m².

    a) pressure p = F1/S1=F2/S2.

    We get: p=F1/S1=20N/0.2m²=100N/m²

    b) force on the other piston:

    F2=p*S2

    F2=100N/m²*2m²=200N

    Answer: p=100N/m², F2=200N
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