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16 January, 04:01

A ball is dropped from the top of a cliff. By the time it reaches the ground, all of its gravitational potential energy has been transferred into kinetic energy. If the ball is travelling at 20m/s when it hits the ground, what height was it dropped from? (Assume that the gravitational field strength is 10N/kg.)

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  1. 16 January, 05:19
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    20 m

    Explanation:

    Initial potential energy = final kinetic energy

    mgh = 1/2 mv²

    gh = 1/2 v²

    h = v² / (2g)

    Given v = 20 m/s and g = 10 m/s²:

    h = (20 m/s) ² / (2 * 10 m/s²)

    h = 20 m
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