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2 May, 08:55

the shape of a four-spoked wheel with a diameter of 185 m. If the space station rotates at a rate of 2.35 revolutions per minute, what is the magnitude of the artificial gravitational acceleration provided to a space tourist walking on the inner wall of the station

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  1. 2 May, 11:28
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    The magnitude of the artificial gravitational acceleration provided to a space tourist walking on the inner wall of the station is 5.6 m/s²

    Explanation:

    Given-

    Diameter, d = 185 m

    radius, r = d/2 = 185/2 = 92.5 m

    Frequency, f = 2.35 rev/min = 2.35/60 rev/sec

    Magnitude of gravitational acceleration, a = ?

    Centripetal acceleration, a = v²/r - 1

    and v = 2πrf

    Substituting the value of v in equation 1

    a = (2πrf) ²/r

    a = 2πrf X 2πf

    a = 4π²rf²

    a = 4 X 3.14 X 3.14 X 92.5 X 2.35 X 2.35 / 60 X 60

    a = 5.6 m/s²

    Therefore, the magnitude of the artificial gravitational acceleration provided to a space tourist walking on the inner wall of the station is 5.6 m/s²
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