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12 May, 13:10

A series circuit has a 100-Ω resistor, 4.00-mH inductor and a 0.100-μF capacitor connected across a 120-V rms ac source at the resonance frequency. What is the power dissipated by the circuit

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  1. 12 May, 14:44
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    144 watt

    Explanation:

    resistance, R = 100 ohm

    L = 4 mH

    C = 100 micro farad

    At resonance, the impedance is equal to R

    Z = R

    Vrms = 120 V

    Irms = Vrms / R = 120 / 100 = 1.2 A

    Power is given by

    P = Vrms x Irms x CosФ

    Where, CosФ is called power factor

    At resonance, CosФ = 1

    Power, P = Irms x Vrms

    P = 1.2 x 120 x 1

    P = 144 Watt.

    Thus, the power is 144 watt.
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