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27 August, 07:20

21 kg brick v=6.1 m/s sticks to a 2.9 kg cart v=.26 m/s

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  1. 27 August, 08:38
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    v = 6.05 m/s

    Explanation:

    The mass of the brick, M = 21 kg

    The velocity of the brick, U = 6.1 m/s

    The mass of the cart, m = 2.9 kg

    The velocity of the cart, u = 0.26 m/s

    The combined mass of the brick and the cart, v = ?

    According to the law of conservation of linear momentum,

    Combined final momentum = sum of the initial momentum

    (M + m) v = MU + mu

    v = MU + mu / M + m

    = 21 x 6.1 + 2.1 x 0.26 / (21 + 0.26)

    = 6.05 m/s

    Hence, the combined velocity of the cart and the brick is, v = 6.05 m/s
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