Acar is moving east along a straight, level road at a constant velocity. Which forces form an action/reaction for

the force of the tires against the road and the force of the road on the tires

the weight of the car and the force of the road pushing up on the car

the force of the engine on the car and the force due to friction on the car

the normal force on the car and the force of the car pulling on Earth

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The force of the tires against the road and the force of road on the tires

The force of the tires against the road and the force of the road on the tires form an action/reaction force pair.

Answer: Option A

Explanation:

The action/reaction force pair came to existence with Newton's third law of motion which states that each action happens with an equal and the opposite reaction. This means for every force exerted on object B by object A will return another force of equal magnitude and opposing direction on object A by object B.

Thus the action and reaction force acting between both the objects tend to form the action/reaction pair. Also, it can also be noted that this pair will occur between contacting forces only. So, out of all the given options, the first option is the correct choice of action/reaction pair.

In that option, the force of tires against the road is the force applied on road by car which is the action form. Then, in its reaction, the friction force is exerted on the tires by the road which is the force of the road on the tires.