A bullet with a mass of 3.0 gram, moving at speed of 300 m/s, hits and embeds itself in the trunk of a tree. The tree exerts an average force of 250 N on the bullet. What is the distance the bullet travels inside the trunk?

Distance the bullet travels inside the trunk is 0.54 m

Explanation:

We have equation for force

Force = Mass x Acceleration

Force = 250 N

Mass = 3 g = 3 x 10⁻³ kg

250 = 3 x 10⁻³ x Acceleration

Acceleration = 83333.33 m/s²

Deceleration of bullet is 83333.33 m/s².

We have equation of motion v² = u² + 2as

Initial velocity, u = 300 m/s

Acceleration, a = - 83333.33 m/s²

Final velocity, v = 0 m/s

Substituting

v² = u² + 2as

0² = 300² + 2 x - 83333.33 x s

s = 0.54 m

Distance the bullet travels inside the trunk is 0.54 m