Ask Question
2 March, 15:13

A 2290 kg car traveling to the west at 22.3 m/s slows down uniformly. How long would it take the car to come to a stop if the force on the car is 8930 N to the east? Let East be positive. Answer in units of s.

+4
Answers (2)
  1. 2 March, 16:21
    0
    5.72 s

    Explanation:

    From Newton's law, F = ma

    The East is + ve direction, Hence,

    F = + 8930 N

    m = 2290 kg

    a = ?

    8930 = 2290 * a

    a = 8930/2290 = 3.90 m/s²

    So, we will find the time it takes the car to stop using the equations of motion

    a = 3.90 m/s²

    u = initial velocity of the car = - 22.3 m/s (the velocity is to the west)

    v = final velocity of the car = 0 m/s (since the car comes to rest)

    t = time taken for the car to come to rest = ?

    v = u + at

    0 = - 22.3 + (3.90) (t)

    3.9t = 22.3

    t = 5.72 s
  2. 2 March, 16:33
    0
    5.72 s.

    Explanation:

    F = 8930 N

    M = 2290 kg

    u = 22.3 m/s

    Note, F = M * a

    a = 8930 : 2290

    = 3.9 m/s^2

    Using equation of motion,

    v = u + at

    22.3 = 3.9t

    t = 5.72 s.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 2290 kg car traveling to the west at 22.3 m/s slows down uniformly. How long would it take the car to come to a stop if the force on the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers