Ask Question
12 October, 04:13

Calculate the effective radiation dosage in sieverts for a 57 57 ‑kg person who is exposed to 4.2 * 10 9 4.2*109 particles of alpha radiation. Only 81 % 81% of the radiation is absorbed. Assume each alpha particle has an energy of 6.1 * 10 - 13 6.1*10-13 J and that the RBE of the alpha particles is 15 15. Note that RBE is sometimes called the quality factor (Q Q).

+5
Answers (1)
  1. 12 October, 06:41
    0
    Dose = 5.4 10⁻⁴ Sv

    Explanation:

    The radiation dose absorbed by the body is 81% of the incident radiation, which is the number of particles per energy of each particle

    E = 0.81 n₀ E₀

    E = 0.81 4.2 10⁹ 0.81 6.1 10⁻¹³

    E = 2.075 10⁻³ J

    Effective radiation dose

    Dose1 = n x RBE

    Dose1 = 2,075 10⁻³ 15

    Dose1 = 3.1 10⁻² REM

    The effective radiation dose in sievert

    Dose = dose1 / m

    Dose = 3.1 10⁻² / 57

    Dose = 5.4 10⁻⁴ [j / kg]

    Dose = 5.4 10⁻⁴ Sv
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the effective radiation dosage in sieverts for a 57 57 ‑kg person who is exposed to 4.2 * 10 9 4.2*109 particles of alpha ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers