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12 March, 16:44

a 1507kg truck enters a corner with a radius of 465m with a centripetal force magnitude of 3410n. What is the truck's speed?

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  1. 12 March, 20:41
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    Answer:32.44m/s

    Explanation:

    Centripetal force = (mass (velocity) ^2) / r

    3410 = (1507v^2) / 465

    Cross product

    3410*465=1507v^2

    1585650=1507v^2

    V^2=1585650/1507

    V^2=1052.189781

    V=√ (1052.189781)

    V=32.44joules
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