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11 November, 13:12

The force required to stretch a Hooke's-law spring varies from 0 N to 43.2 N as we stretch the spring by moving one end 14.4 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.

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  1. 11 November, 15:26
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    Spring constant = 300 N/m

    Explanation:

    For a spring we have force is the product of spring constant and displacement.

    Force = Spring constant x Displacement

    F = k x

    Here Force, F = 43.2 - 0 = 43.2 N

    Displacement, x = 14.4 cm = 0.144 m

    Substituting

    F = k x

    43.2 = k x 0.144

    k = 300 N/m

    Spring constant = 300 N/m
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