A statue is to be 'scaled down.' It will have its size changed without changing its shape. It starts with an initial volume of 3.25 m3 and ends up with a final volume of 1.00 m3.

The solution are in the explanation

Explanation:

Volume varies with the cube of the linear dimension

Ratio of volumes is 3:1, therefore the ratio of the linear dimensions is 3^ (1/3) : 1 = 1.442:1

Smaller statue is 350/1.442 cm = 242.7 cm

C = pi*D, D is a linear dimension, so Ds = 50/1.442 = 34.67 cm

Area varies with the square of the linear dimension; so the ratio of the areas will be (1/3) ^ (2/3) = 0.48; the surface area of the smaller statue will be 0.48 that of the original

The mass of the model would vary directly with the volume, so the mass of the model will be 1/3 that of the original

If the masses of the models are the same, then the model must be made of a material 3x the density of that used for the original.