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24 December, 12:17

A 6.25 L tank holds helium gas at a pressure of 1759 psi. A second 6.25 L tank holds oxygen at a pressure of 467.7 psi. The two gases are mixed in a 6.25 L tank. If the temperature remains the same throughout the process, what is the pressure of the gas mixture in the tank? Assume ideal gas behavior.

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  1. 24 December, 12:45
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    P=1113.35 psi

    Explanation:

    For tank 1

    V₁ = 6.25 L

    P₁=1759 psi

    For tank 2

    V₂=6.25 L

    P₂=467.7 psi

    Lets take final pressure is P

    The final volume V = 6.25 + 6.25 L = 12.5 L

    P V = V₂P₂+V₁P₁

    Now by putting the values

    P V = V₂P₂+V₁P₁

    P x 12.5 = 6.25 x 467.7+6.25 x 1759

    P=1113.35 psi

    So the final volume of the system will be 1113.35 psi.
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