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25 March, 16:03

A current of 250 amps is flowing through a copper wire with a resistance of

2.09 x 10^-4 ohms. What is the voltage?

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Answers (1)
  1. 25 March, 17:41
    0
    V = 5.225*10^-2 volts

    Explanation:

    from ohms law

    V=IR

    where R = 2.09*10^-4

    I=250A

    V=2.09*10^-4*250

    V = 5.225*10^-2 volts
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