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30 May, 20:30

The velocity of a particle which moves along the s-axis

is given by s=40-3t^2 where t is in seconds.

Calculate the displacement delta s of the particle during

the interval from t=2 to t=4

+3
Answers (1)
  1. 30 May, 22:32
    0
    24 units

    Explanation:

    Δs = ∫ v (t) dt

    Δs = ∫₂⁴ (40 - 3t²) dt

    Δs = (40t - t³) |₂⁴

    Δs = (40 (4) - (4) ³) - (40 (2) - (2) ³)

    Δs = (160 - 64) - (80 - 8)

    Δs = 96 - 72

    Δs = 24
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