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Yesterday, 13:05

A cart starts at x = + 6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position (in m) 3.0 seconds later?

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  1. Yesterday, 16:30
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    At the origin (x' = 0 m)

    Explanation:

    Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

    The formula of speed is given as

    S = d/t ... Equation 1

    Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

    make d the subject of the equation,

    d = St ... Equation 2

    Given: S = 2.0 m/s, t = 3.0 s

    Substitute into equation 2

    d = 2 (3)

    d = 6 m.

    From the above, the cart covered a distance of 6 m in 3 s.

    The exact position of the cart = Initial position-distance covered

    x' = x-d ... Equation 3

    Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

    Given: x = + 6.0 m, d = 6 m.

    Substitute into equation 3

    x' = + 6-6

    x' = 0 m.

    Hence the cart will be at 0 m (origin) 3 s later
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