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11 April, 11:07

V=vi+at^2 dimensional correct

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  1. 11 April, 13:47
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    Yes, dimensionally the equation is correct.

    Explanation:

    This equation is the kinematic equation for uniformly accelerated motion, then we study the units of each member to conclude whether it is dimensionally correct.

    vi = initial velocity [m/s]

    a = acceleration [m/s^2]

    t = time [s]

    v = final velocity

    therefore we have:

    [m/s] + [m/s^2]*[t^2], the second term now is m/s

    [m/s] + [m/s] = [m/s]

    So the analysis is correct.
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