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Jaylen Calhoun
11 April, 11:07
V=vi+at^2 dimensional correct
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Kolten Hopkins
11 April, 13:47
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Yes, dimensionally the equation is correct.
Explanation:
This equation is the kinematic equation for uniformly accelerated motion, then we study the units of each member to conclude whether it is dimensionally correct.
vi = initial velocity [m/s]
a = acceleration [m/s^2]
t = time [s]
v = final velocity
therefore we have:
[m/s] + [m/s^2]*[t^2], the second term now is m/s
[m/s] + [m/s] = [m/s]
So the analysis is correct.
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