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24 August, 17:03

A car travels along a straight line at a constant speed of 60.0 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 30.0 mi/h. (a) What is the constant speed with which the car moved during the second distance d

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  1. 24 August, 20:58
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    velocity during second d = 20.0 mi/h

    Explanation:

    Total distance travelled is 2d, with an average velocity of 30.0 mi/h you can express the time travelled in terms of d:

    distance = velocity * time

    time = distance / velocity

    time = 2d/30.0

    The time needed for the first d at 60.0 is:

    time = d/60.0

    The time in the second d you can get it by substracting both times (total time - time for the first d)

    second d time = 2d/30.0 - d/60.0

    = 4d/60.0 - d/60.0

    = 3d/60.0

    and with the time (3d/60.0) and the distance travelled (d) you can get the velocity:

    velocity = distance / time

    velocity = d / (3d/60.0)

    = 60.0/3 = 20.0 mi/h
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