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4 August, 22:29

Two trains are moving at 30 m/s in opposite directions on the same track. The engineers see simultaneously that they are on a collision course and apply the brakes when they are 1000 m apart. Assuming both trains have the same acceleration, what must this acceleration be if the trains are to stop just short of colliding?

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  1. 4 August, 22:37
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    Acceleration of train needed to avoid collision = - 0.9 m/s²

    Explanation:

    Here both trains are similar with 1000 m apart with same speed.

    So one train has to move 500 m before stopping just to avoid collision.

    We have

    Initial velocity, u = 30 m/s

    Acceleration, a = ?

    Displacement, s = 500 m

    Final velocity, v = 0 m/s

    We have equation of motion v² = u² + 2as

    Substituting

    v² = u² + 2as

    0² = 30² + 2 x a x 500

    a = - 0.9 m/s²

    Acceleration of train needed to avoid collision = - 0.9 m/s²
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