The battery of a flashlight develops 3 V, and the current through the bulb is 200 mA. What power is absorbed by the bulb?

Answer : The power absorbed by the bulb is, 0.600 W

Explanation:

As we know that,

Power = Voltage * Current

Given:

Voltage = 3 V

Current = 200 mA = 0.200 A

Conversion used : (1 mA = 0.001 A)

Now put all the given values in the above formula, we get:

Power = Voltage * Current

Power = 3V * 0.200 A

Power = 0.600 W

Thus, the power absorbed by the bulb is, 0.600 W