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13 August, 07:48

1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm. calculate the stress developed in the bar

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  1. 13 August, 11:18
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    Answer:25N/M^2

    Explanation:

    Force=20N Area=0.8M^2

    Stress=force/area

    Stress=20/0.8

    Stress=25N/M^2
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