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20 October, 12:09

A car is traveling with a constant speed of 30.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with a constant acceleration. The car comes to a stop in a distance of 120 m. What was the acceleration of the car as it slowed down?

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  1. 20 October, 13:58
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    a = - 3.75 m/s²

    negative sign indicates deceleration here.

    Explanation:

    In order to find the constant deceleration of the car, as it stops, we will use the 3rd equation of motion. The 3rd equation of motion is as follows:

    2as = Vf² - Vi²

    a = (Vf² - Vi²) / 2s

    where,

    a = deceleration of the car = ?

    Vf = Final Velocity = 0 m/s (Since, the car finally stops)

    Vi = Initial Velocity = 30 m/s

    s = distance covered by the car = 120 m

    Therefore,

    a = [ (0 m/s) ² - (30 m/s) ²] / (2) (120 m)

    a = - 3.75 m/s²

    negative sign indicates deceleration here.
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