Ask Question
14 July, 08:20

A 0.5-kg cart moving on a horizontal frictionless track at 0.6 m/s hits a solid bumber and bounces back with a speed of 0.4 m/s. The impulse on the cart is?

+1
Answers (1)
  1. 14 July, 08:55
    0
    I = 0.5 kg. m/s

    Explanation:

    given,

    mass of the cart = 0.5 Kg

    initial speed of cart, u = 0.6 m/s

    final speed of cart, v = - 0.4 m/s

    impulse of the cart = ?

    impulse is equal to the change of the momentum of the cart.

    I = m u - m v

    I = m (u - v)

    I = 0.5 (0.6 - (-0.4))

    I = 0.5 x 1

    I = 0.5 kg. m/s

    impulse on the cart is equal to 0.5 kg. m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 0.5-kg cart moving on a horizontal frictionless track at 0.6 m/s hits a solid bumber and bounces back with a speed of 0.4 m/s. The ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers