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11 April, 12:39

The net electric flux through a cubic box with sides that are 22.0 cm long is 4.90 * 10 3 N ⋅ m 2 / C 4.90*103 N⋅m2/C. What charge Q is enclosed by the box?

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  1. 11 April, 16:12
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    Q = 43.4 nC

    Explanation:

    According to the Gauss Law, the net electric flux through a closed surface, is equal to the charge enclosed by this surface, divided by the permitivitty of the free space, as follows:

    Flux = Q/ε₀

    If we know that the net electric flux through a cubic box with sides that are 22 cm. long, is 4.9*10³ N*m²/C, we can find the enclosed charge, defining a gaussian surface identical to this cube, as follows:

    Qenc = 4.9*10³ N*m²/C * 8.85*10⁻¹² C²/N*m² = 43.4*10⁻⁹ C = 43.4 nC
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