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20 May, 07:38

Should the antireflection coating of a microscope objective lens designed for use with ultraviolet light be thinner, thicker, or the same thickness as the coating on a lens designed for visible light?

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  1. 20 May, 09:08
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    the thickness to meet the equation must be less than in a system for visible Liz t _UV < t_visible

    Explanation:

    When a ray enters the film antireflector that generally has a refractive index greater than the glass index, it experiences a phase change of 180, similar to when we have a collision with a wall.

    When the beam reaches the bottom of the film-glass interface film, the refractive impact of the film is greater than that of the glass, it does not experience any change in phase.

    Within the film the beam experiences a change in its propagation speed, the frequency in the air and the film is the same, since the propagation of a resonant type process, to fulfill the equation

    v = λₙ f

    The wavelength must change c = λ₀ f

    c / v = λ₀ / λₙ

    n = λ₀ / λₙ

    λₙ = λ₀ / n

    In general this type of reflection is almost normal to the surface, so we can calculate the optical path difference, if t is the thickness of the film, for constructive interference

    2t = m λₙ + λₙ / 2

    2t = (m + ½) λₙ

    This is the condition to see a bright beam.], For destructive interference the equation is

    2t = m λₙ

    t = m λₙ / 2

    Since the wavelength of visible light 400 to 700 is not much male than the wavelength of ultra violet light Lam <400 no, the thickness to meet the equation must be less than in a system for visible Liz

    t _UV < t_visible
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