On Venus, the acceleration due to gravity is 8.87 m / s 2. How far would a 17 g rock fall from rest in 6.5 s if the only force acting on it was the gravitational force due to Venus?

187.38 m

Explanation:

Using the equation of motion

s = ut + 1/2gt² ... Equation 1

Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.

Given: u = 0 m/s (from rest), t = 6.5 s, g = 8.87 m/s².

substituting into equation 1

s = 0 (6.5) + 1/2 (8.87) (6.5) ²

s = 0 + 374.7575/2

s = 187.38 m.

Hence the rock will fall 187.38 m