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6 November, 08:01

An ion with charge of Q = + 3.2 x 10-19 C is in a region where a uniform electric field of magnitude E = 5.0 x 105 V/m is perpendicular to a uniform magnetic field B = 0.80 T. If the ion's acceleration is zero then what is its speed v? a) v = 1.6 x 10-5 m/s b) v = 4.0 x 105 m/s c) v = 6.3 x 10 m/s d) V = 0 m/s

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  1. 6 November, 09:29
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    speed is 6.3 * 10^5 m/s

    Explanation:

    given data

    charge Q = + 3.2 x 10^-19 C

    uniform electric field E = 5.0 x 10^5 V/m

    uniform magnetic field B = 0.80 T

    acceleration = 0

    to find out

    speed

    solution

    we know here that acceleration = 0

    so that force on uniform electric field E and uniform magnetic field B on charge particle = 0

    so here force of magnitude will be equal

    so we can say that

    q*E = q*v*B ... 1

    so v = E / B

    put here value

    v = 5 * 10^5 / 0.80

    v = 6.3 * 10^5

    so speed is 6.3 * 10^5 m/s
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