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17 November, 21:36

Solar cells are given antireflection coatings to maximize their efficiency. Consider a silicon solar cell (n = 3.50) coated with a layer of silicon dioxide (n = 1.45). What is the minimum coating thickness that will minimize the reflection at the wavelength of 700 nm, where solar cells are most efficient?

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  1. 17 November, 23:30
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    t = 121 nm

    Explanation:

    Given:

    - Silicon refractive index n_1 = 3.50

    - Silicon dioxide refractive index n_2 = 1.45

    - The wavelength of light in air λ_air = 700 nm

    Find:

    What is the minimum coating thickness that will minimize the reflection at the wavelength of 700 nm.

    Solution:

    - The film's index of refraction (n_2 = 1.45) is less than that of solar cell (n_1 = 3.50) so there will be a reflective phase change at the first boundary (air-film), and at the second boundary (film-solar cell). The relationship for destructive interference for two reflective phase changes is as follows:

    2*t = (m + 0.5) * (λ/n_2) m = 0, 1, 2, ...

    - Solve for thickness t where m = 0 (for the thinnest film).

    t = 0.25 * (λ/n_2)

    t = 0.25 * (700/1.45)

    t = 121 nm ... (rounded to 3 sig. fig)

    - This coating technique is important to increase the efficiency of solar cells; If the light can't reflect, then it must transmit into the solar cell material.
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