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25 September, 10:46

What is the width of a slit for which the first minimum is at 45° when the slit is illuminated by a helium-neon laser (λ = 633 nm) ?

Hint: The small-angle approximation is not valid at 45°.

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  1. 25 September, 11:28
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    d = 895 nm

    Explanation:

    Given:

    - Wavelength of light λ = 633 nm

    - Angle Q is between central order = 45 degrees

    Find:

    What is the width of a slit?

    Solution:

    - The relationship between and wavelength and the order of fringes with respect to slit size d is given by Young's experiment as follows:

    sin (Q) = m*λ / d

    - Use the above result and compute for the grating d for m = 1,

    d = λ / sin (Q)

    d = 633*10^-9 / sin (45)

    d = 0.89 um

    - The width of slit is d = 895 nm
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