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Today, 15:45

When a mass is placed on a spring with a spring constant of 15 newtons per meter, the spring is compressed 0.25 meter. How much elastic potential energy is stored in the spring?

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  1. Today, 15:50
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    0.47 J

    Explanation:

    The elastic potential energy of a spring is given as,

    E = 1/2ke² ... Equation 1

    Where E = Elastic potential energy, k = spring constant, e = extension/compression.

    Given: k = 15 N/m, e = 0.25 m.

    Substitute into equation 1.

    E = 1/2 (15) (0.25) ²

    E = 0.46875

    E ≈ 0.47 J.

    Hence the elastic potential energy stored in the spring = 0.47 J
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