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18 October, 09:26

3.

A 2,000-kilogram car uses a braking force of 12,000 newtons to stop in 5 seconds.

a. What impulse acts on the car?

b. What is the change in momentum of the car?

c. What is the initial speed of the car?

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Answers (1)
  1. 18 October, 11:46
    0
    m = 2,000-kilogram

    F = 12,000

    t = 5 seconds

    a) Impulse (I) = Ft = 12000 * 5

    I = 60,000 Ns

    b) from Newton's 2nd law

    F = m∆v/t

    Ft = m∆v

    change in momentum (∆p) = 60,000kgm/s

    c) ∆v = Ft/m = 60,000/2000 = 30m/s

    the initial velocity is 30m/s since final velocity is zero

    Momentum ...

    is a quantity that describes an object's

    resistance to stopping (a kind of "moving

    inertia"). and is represented by the symbol p which is the product of an object's mass and velocity.

    p = m v

    is a vector quantity (since velocity is a

    vector and mass is a scalar).

    Impulse ...

    is a quantity that describes the effect of a

    net force acting on an object (a kind of

    "moving force").

    is represented by the symbol I

    is the product of the average net force

    acting on an object and its duration.

    I = F Δ t
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