As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160-T magnetic field near the center of the solenoid. You have enough wire for 4300 circular turns. This solenoid must be 1.10 m long and 3.50 cm in diameter. What current will you need to produce the necessary field?

Question

Physics

Sloane Davidson

18 January, 06:09

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160-T magnetic field near the center of the solenoid. You have enough wire for 4300 circular turns. This solenoid must be 1.10 m long and 3.50 cm in diameter. What current will you need to produce the necessary field?

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Answers (1)

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Lilyana Benson · Answer 1

Current = 32.6 A

Explanation:

Magnetic field = B = 0.160 T

No. of turns of coil = N = 4300

Length of the solenoid = L = 1.10 m

Current required depends on the B, L, N and the magnetic permeability μ₀

B = μ₀ N I / L

⇒ Current = I = B L / μ₀N = (0.160) (1.10) / (4π * 10⁻⁷) (4300)

= 32.6 A