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15 June, 20:18

What horizontally-applied force will accelerate a 400-kg crate at 1 m/s^2 across a factory room floor against a friction force of half its weight?

A) 600 N B) 1600 N C) 2000 N D) 2400 N E) None of the above

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  1. 15 June, 20:53
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    option D

    Explanation:

    given,

    mass of the crate = 400 Kg

    acceleration of the crate = 1 m/s²

    frictional force = half its weight

    weight of the crate, = mg

    = 400 x 10 = 4000 N

    frictional force, f = 0.5 x 4000 = 2000 N

    using newtons second law

    F - f = m a

    F = m a + f

    F = 400 x 1 + 2000

    F = 2400 N

    Horizontal force applied is equal to 2400 N

    The correct answer is option D
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