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13 July, 00:20

If you exert a horizontal force of 200 N to slide a crate across a factory floor at constant velocity, how much friction is exerted by the floor on the crate?

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  1. 13 July, 00:26
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    200 N

    Explanation:

    Applied force, F = 200 N

    Let the friction force is f.

    By use of Newton's second law

    Net force = mass * acceleration

    F - f = m * a

    Here acceleration a is zero as crate moves with constant velocity.

    So, F - f = 0

    f = F

    Friction force = 200 N
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